.2x^2=5.6

Solution for .2x^2=5.6 equation:

.2x^2=5.6

We move all terms to the left:

.2x^2-(5.6)=0

We add all the numbers together, and all the variables

.2x^2-5.6=0

a = .2; b = 0; c = -5.6;
Δ = b2-4ac
Δ = 02-4·.2·(-5.6)
Δ = 4.48
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{4.48}}{2*.2}=\frac{0-\sqrt{4.48}}{0.4}
=-\frac{\sqrt{}}{0.4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{4.48}}{2*.2}=\frac{0+\sqrt{4.48}}{0.4}
=\frac{\sqrt{}}{0.4}
$